Fibonacci series in Swift

Fibonacci.swift

// Fibonacci series
// F[n] = F[n-1] + F[n-2]
// 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144
// Find the fibonacci number for n interations

func fibonacci(n: Int) {

    var num1 = 0
    var num2 = 1

    for _ in 0 ..< n {
    
        let num = num1 + num2
        num1 = num2
        num2 = num
    }
    
    print("result = \(num2)")
}
fibonacci(7)


// Using Recursion
func fibonacciRecursiveNum1(num1: Int, num2: Int, steps: Int) {

    if steps > 0 {
        let newNum = num1 + num2
        fibonacciRecursiveNum1(num2, num2: newNum, steps: steps-1)
    }
    else {
        print("result = \(num2)")
    }
}
fibonacciRecursiveNum1(0, num2: 1, steps: 7)

This is being a bit clever:

/// Generates a series of `numberOfElements` many fibonacci element, using recursion.
func fibonnaci(numberOfElements n: UInt) -> [Int] {
	let list = [0, 1]
	guard n > 2 else {
		return Array(list.prefix(Int(n)))
	}
	
	func inner(_ l: [Int]) -> [Int] {
		let m = l.count
		guard n != m else { return l }
		return inner(l + [(l[m - 2] + l[m - 1])])
	}
	
	return inner(list)
}