:uid: anisotropic-conductivity :title: Anisotropic Conductivity :description: when electrical conductivity varies with direction :tooltip: None :tag: conductivity,anisotropy,dc,em,physical properties :group: simpeg :license: CC-BY-4.0 :source: https://api.github.com/gists/56c47e9a872aa908705d
When a physical property of a material varies with direction, that material is anisotropic (not to be confused with heterogeneity. Check out Matt Hall's discussion on anisotropy). Anisotropy in electrical conductivity can have a variety of causes. To name a few:
- alignment of cracks or pores,
- bedding / lamination,
- alignment of mineral grains.
Any of these, or similar phenomena can create preferential directions
for current to flow. To examine this a bit, lets look at the constitutive relation that relates the current density
In an isotropic medium,
In an anisotropic medium,
Lets break this down and consider a few examples. Since drawing vectors and such is easier in 2D, lets consider a 2D example, where everything is happening in the x-z plane. In the figure below, we have a "rock" that is blue and gray.
The blue regions are conductive and the gray regions are resistive. If we apply an electric field in the x-direction, the charges have a choice to either go through the resistive or conductive region, like a parallel circuit. If instead we apply an electric field in the z-direction, the charges have no choice which medium they can go through.
If we want to describe the conductivity of this rock, we use a
If we excite this with an electric field oriented in the
$$ \vec{J}_{1}
In a similar vein, if we use an electric field oriented in the
$$ \vec{J}_{2}
So we can multiply a matrix and a vector! Thats not why I am showing you this... lets have a look at the magnitude of the current density in each case. For the first case, we have that
$$ |\vec{J}{1}| = \sigma{xx} E_{x} $$
and in the second case,
$$ |\vec{J}{2}| = \sigma{zz} E_{z} $$
For the example here, we know that \sigma_{xx} > \sigma_{zz}. So if the magnitude of the inducing field is identical in both cases, the resulting current density magnitude is different between the two, namely $|\vec{J}{1}| > |\vec{J}2|$. So if we wanted the current density to be same, we need to apply a bigger push in the $z$-direction; in particular, we would need: $E{z} = \sigma{xx}/\sigma_{zz} E_x$.
In this example, everything lined up with our coordinate system, so the various components didn't talk to each other. Lets change that.
I started planning on writing this about the behavior of anisotropy in cylindrically symmetric settings, but got a bit sidetracked. Anyways, that will come at another time!
http://www.agilegeoscience.com/blog/2015/2/9/what-is-anisotropy