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February 17, 2023 13:32
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记录一个python正则匹配的坑
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import re | |
# 待匹配的字符串 | |
s = '[AB=1231][AC=23] [AC=3,as=12]' | |
# 匹配的规则 | |
rule = r'(\[AC\=\d+(,[a-z]+\=\S+)*\])' | |
# 结果: [('[AC=23]', ''), ('[AC=3,as=12]', ',as=12')] | |
print(re.findall(rule, s)) | |
## 下面是一些教训总结 | |
# re.match 只能匹配开头的子字符串 | |
# re.search 只能匹配第一个出现的子字符串 | |
# re.findall 如果不使用捕获组,它会返回 `['', ',as=12']`, 非重叠部分 |
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