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Imperative and Functional coding in Python
from itertools import groupby
from operator import itemgetter
name, age, tech, skill = range(0, 4)
data = [
['alice', 24, 'blue', 86],
['alice', 24, 'green', 80],
['bob', 20, 'red', 76],
['bob', 20, 'green', 68],
['charlie', 45, 'blue', 96],
['dylan', 32, 'blue', 75],
['dylan', 32, 'green', 81],
['dylan', 32, 'red', 54],
['evelyn', 29, 'green', 83],
['evelyn', 29, 'red', 78],
['francis', 19, 'red', 64]
]
def get_answer_imperative(_data):
answer = {}
for row in _data:
if row[age] >= 40:
continue
if row[tech] in answer:
answer[row[tech]] = max(answer[row[tech]], (row[skill], row[name]))
else:
answer[row[tech]] = (row[skill], row[name])
return {_tech: skill_name[1] for (_tech, skill_name) in answer.items()}
def get_answer_functional(_data):
return dict(
map(
lambda (_tech, rows): (_tech, max(rows, key=itemgetter(skill))[name]),
groupby(
sorted(
filter(
lambda row: row[age] < 40,
_data
),
key=itemgetter(tech)
),
lambda groups: groups[tech]
)
)
)
if __name__ == '__main__':
print('Imperative Answer: {0}'.format(get_answer_imperative(data)))
print('Functional Answer: {0}'.format(get_answer_functional(data)))
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