[C#] MultiPartFormDataContent, Upload multi files to server at a time.

example2.cs

System.Net.Http.HttpRequestMessage request = new System.Net.Http.HttpRequestMessage(System.Net.Http.HttpMethod.Post, _serverUri);

MultipartFormDataContent form = new MultipartFormDataContent();
request.Content = form;

HttpContent content1 = new ByteArrayContent(filePart1);
content1.Headers.ContentDisposition = new ContentDispositionHeaderValue("filePart1");
content1.Headers.ContentDisposition.FileName = "filePart1";
form.Add(content1);

HttpContent content2 = new ByteArrayContent(filePart2);
content2.Headers.ContentDisposition = new ContentDispositionHeaderValue("filePart2");
content2.Headers.ContentDisposition.FileName = "filePart2";
form.Add(content2);

_httpClient.SendAsync(request).ContinueWith((response) =>
{
        ProcessResponse(response.Result);
});

SendFileToServer.cs

private static void SendFileToServer(string fileFullPath)
        {
            FileInfo fi = new FileInfo(fileFullPath);
            string fileName = fi.Name;
            byte[] fileContents = File.ReadAllBytes(fi.FullName);
            Uri webService = new Uri(@"http://avalidwebservice.com");
            HttpRequestMessage requestMessage = new HttpRequestMessage(HttpMethod.Post, webService);
            requestMessage.Headers.ExpectContinue = false;

            MultipartFormDataContent multiPartContent = new MultipartFormDataContent("----MyGreatBoundary");
            ByteArrayContent byteArrayContent = new ByteArrayContent(fileContents);
            byteArrayContent.Headers.Add("Content-Type", "application/octet-stream");
            multiPartContent.Add(byteArrayContent, "this is the name of the content", fileName);
            requestMessage.Content = multiPartContent;

            HttpClient httpClient = new HttpClient();
            try
            {
                Task<HttpResponseMessage> httpRequest = httpClient.SendAsync(requestMessage, HttpCompletionOption.ResponseContentRead, CancellationToken.None);
                HttpResponseMessage httpResponse = httpRequest.Result;
                HttpStatusCode statusCode = httpResponse.StatusCode;
                HttpContent responseContent = httpResponse.Content;

                if (responseContent != null)
                {
                    Task<String> stringContentsTask = responseContent.ReadAsStringAsync();
                    String stringContents = stringContentsTask.Result;
                }
            }
            catch (Exception ex)
            {
                Console.WriteLine(ex.Message);
            }
        }

Hi, It was very helpful this example.

I am testing one of the REST API ( pdf file post ) in Postman client. I got the below c# code form Postman. I want to do this programmatically. Do you have any idea how do i achieve using multipart form data.

var client = new RestClient("https://sest-stg.dev03.sbc.ase.central.us.hal.net/files/v1");
var request = new RestRequest(Method.POST);
request.AddHeader("Postman-Token", "cee45074-d613-4e58-ac25");
request.AddHeader("cache-control", "no-cache");
request.AddHeader("Content-Type", "application/pdf");
request.AddHeader("X-SM-Client-Id", "94437320-3bcf-498d-915a");
request.AddHeader("Sest-Tenant-Id", "0d3ad0cd-3bb3-4fc0-bd15");
request.AddHeader("content-type", "multipart/form-data; boundary=----WebKitFormBoundary7MA4YWxkTrZu0gW");
request.AddParameter("multipart/form-data; boundary=----WebKitFormBoundary7MA4YWxkTrZu0gW", "------WebKitFormBoundary7MA4YWxkTrZu0gW\r\nContent-Disposition: form-data; name="file"; filename="C_70_4_01302013_101.pdf"\r\nContent-Type: application/pdf\r\n\r\n\r\n------WebKitFormBoundary7MA4YWxkTrZu0gW\r\nContent-Disposition: form-data; name="metadata"\r\n\r\n\r\n------WebKitFormBoundary7MA4YWxkTrZu0gW--", ParameterType.RequestBody);
IRestResponse response = client.Execute(request);