Re: Algorithm for Area of a closed polygon.
To: Ted Hill <firstname.lastname@example.org> Subject: Re: Algorithm for Area of a closed polygon. From: "Demian M. Nave" <email@example.com> Date: Wed, 12 Nov 2003 21:23:16 -0500 (EST) Cc: <firstname.lastname@example.org> In-reply-to: <1E2E66102E75104D8C740340EBCD98671BC279@tomoex.tomotherapy.com> References: <1E2E66102E75104D8C740340EBCD98671BC279@tomoex.tomotherapy.com> Reply-to: Demian Nave <email@example.com>
I want to be able to calculate the area inside a closed many-sided polygon.
As long as your polygon has no self-crossings or internal holes, this algorithm is probably the simplest. It will return twice the signed area of your polygon:
Let 'vertices' be an array of N pairs (x,y), indexed from 0 Let 'area' = 0.0 for i = 0 to N-1, do Let j = (i+1) mod N Let area = area + vertices[i].x * vertices[j].y Let area = area - vertices[i].y * vertices[j].x end for Return 'area'
If the vertices of your polygon are specified in counter-clockwise order (i.e. by the right-hand rule), then the area will be positive. Otherwise, the area will be negative, assuming the polygon has non-zero area to begin with.
Hope this helps. Send another note to the mailing list if not. :-)
Demian M. Nave | firstname.lastname@example.org | Ph 412 268-4574 Pgh. Supercomputing Center | www.psc.edu/~dnave | Fx 412 268-8200- 4400 Fifth Avenue | "When your work speaks for itself, don't Pittsburgh, PA 15213 | interrupt." - Kanin
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