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Typescript写的双链表数据结构,可以拿来刷leetcode,用来弥补js没有自带双链表的不足
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class LinkedListNode<T>{ | |
value: T; | |
next: LinkedListNode<T>; | |
prev: LinkedListNode<T>; | |
constructor(value?:T, next?: LinkedListNode<T>, prev?: LinkedListNode<T>){ | |
this.value = value; | |
this.next = next; | |
this.prev = prev; | |
} | |
} | |
class LinkedList<T> { | |
private head = new LinkedListNode<T>(); | |
private tail = new LinkedListNode<T>(); | |
private _length = 0; | |
get length():number{ | |
return this._length; | |
} | |
private set length(value: number){ | |
this._length = value; | |
} | |
constructor(){ | |
this.head.next = this.tail; | |
this.tail.prev = this.head; | |
} | |
first():T{ | |
return this.action(this.head.next, 'get'); | |
} | |
last():T{ | |
return this.action(this.tail.prev, 'get'); | |
} | |
push(value:T){ | |
this.action(this.tail.prev, 'add', value); | |
} | |
pop():T{ | |
const last = this.last(); | |
this.action(this.tail.prev, 'delete'); | |
return last; | |
} | |
shift():T{ | |
const first = this.first(); | |
this.action(this.head.next, 'delete'); | |
return first; | |
} | |
unshift(value:T){ | |
this.action(this.head.next, 'add', value); | |
} | |
get(index: LinkedListNode<T> | number): T{ | |
return this.action(this.search(index), 'get'); | |
} | |
set(index: LinkedListNode<T> | number, value: T){ | |
this.action(this.search(index), 'set', value); | |
} | |
add(index: LinkedListNode<T> | number, value: T){ | |
this.action(this.search(index), 'add', value); | |
} | |
delete(index: LinkedListNode<T> | number){ | |
this.action(this.search(index), 'delete'); | |
} | |
action(p: LinkedListNode<T>, actionType: 'get'|'set'|'add'|'delete', value?:T): T{ | |
if(!p || ((p === this.head || p === this.tail) && actionType !== 'add')){ | |
return; | |
} | |
switch(actionType){ | |
case 'get':{ | |
return p.value; | |
} | |
case 'set':{ | |
p.value = value; | |
break; | |
} | |
case 'add':{ | |
const node = new LinkedListNode(value, p.next, p); | |
p.next.prev = node; | |
p.next = node; | |
this.length++; | |
break; | |
} | |
case 'delete':{ | |
p.next.prev = p.prev; | |
p.prev.next = p.next; | |
this.length--; | |
break; | |
} | |
} | |
} | |
search(index: number | LinkedListNode<T>, direction: 'forward'|'backward' = 'forward'): LinkedListNode<T>{ | |
let p; | |
if(index instanceof LinkedListNode){ | |
if(direction==='backward'){ | |
p = this.head; | |
while(p && p!==index){ | |
p = p.next; | |
} | |
}else{ | |
p = this.tail; | |
while(p && p!==index){ | |
p = p.prev; | |
} | |
} | |
return p; | |
} else if(typeof index === 'number') { | |
const i = Math.abs(index); | |
if(index<0){ | |
p = this.tail; | |
for(let j=0;j<i && p;j++){ | |
p = p.prev; | |
} | |
}else{ | |
p = this.head; | |
for(let j=-1;j<i && p;j++){ | |
p = p.next; | |
} | |
} | |
} | |
return p; | |
} | |
} |
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