exe path in golang

exepath.go

package main

 import (
    "fmt"
    "log"
    "os"
    "path/filepath"
 )

 func main () {

    filename := os.Args[1] // get command line first parameter

    filedirectory := filepath.Dir(filename)

    thepath, err := filepath.Abs(filedirectory)

    if err != nil {
       log.Fatal(err)
    }

    fmt.Println(thepath)
 }
 
 // provided by https://www.socketloop.com/tutorials/golang-get-current-file-path-of-a-file