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@lizrice
Created August 25, 2016 10:02
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Container from scratch
package main
// @lizrice, mostly copied from @doctor_julz: https://gist.github.com/julz/c0017fa7a40de0543001
import (
"fmt"
"os"
"os/exec"
"syscall"
)
// docker run <container> command args
// go run main.go run command args
func main() {
switch os.Args[1] {
case "run":
run()
case "child":
child()
default:
panic("what?")
}
}
func run() {
cmd := exec.Command("/proc/self/exe", append([]string{"child"}, os.Args[2:]...)...)
cmd.Stdin = os.Stdin
cmd.Stderr = os.Stderr
cmd.Stdout = os.Stdout
cmd.SysProcAttr = &syscall.SysProcAttr{
Cloneflags: syscall.CLONE_NEWUTS | syscall.CLONE_NEWPID | syscall.CLONE_NEWNS,
}
must(cmd.Run())
}
func child() {
fmt.Printf("running %v as pid %d\n", os.Args[2:], os.Getpid())
cmd := exec.Command(os.Args[2], os.Args[3:]...)
cmd.Stdin = os.Stdin
cmd.Stderr = os.Stderr
cmd.Stdout = os.Stdout
must(syscall.Chroot("/home/rootfs"))
must(os.Chdir("/"))
must(syscall.Mount("proc", "proc", "proc", 0, ""))
must(cmd.Run())
}
func must(err error) {
if err != nil {
panic(err)
}
}
@mikeschinkel
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@mugli — Sorry I did not see your question when you originally posted it. My answer is:

"No, I was and still am running on Intel macOS."

@dennisberg13100 — Thanks for the comment. Unfortunately my comment was so long ago I've lost a bit of the plot.
But that's okay, I now realize that this was meant for running on Linux and not macOS as I am less of a Go/Linux newbie nowadays.

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