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Last active August 11, 2018 19:47
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range() without loops or recursion… or is it?
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.js
(f => (g => g(g))(g => f(x => g(g)(x))))((x) => ([a, b, c = 1]) => a === b ? [a] : [a, ...x([a + c, b, c])])([1, 10])
// [ 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 ]
// Note: Functional programmers and mathematicians have known this trick
// for decades under the name of a Y combinator. I did not invent this.
// I recommend deciphering this thing on your own, though.
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