Last active
December 7, 2015 23:43
-
-
Save lrlucena/70811b06b124893f676c to your computer and use it in GitHub Desktop.
Qual o valor de x na equação: (x+3)! + (x+2)! = 8(x+1)!
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
| f(x: Inteiro): Inteiro = escolha x | |
| caso 0 => 1 | |
| caso n => n * f(n - 1) | |
| fim | |
| solução = | |
| para x de 0 até 10 se f(x + 3) + f(x + 2) == 8 * f(x + 1) gere x fim | |
| escreva solução |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment
Resolvendo algebricamente:
(x+3)! + (x+2)! = 8 * (x+1)!
(x+3)(x+2)(x+1)! + (x+2)(x+1)! = 8 * (x+1)!
(x+3)(x+2)+(x+2) = 8 , x>=0
(x+4)_(x+2) = 8
x^2+6_x = 0
x * (x + 6) = 0
x' = 0
x'' = -6 (viola a condição x>=0)