Javascript - Replacing the escape character in a string literal

gistfile1.js

//www.lsauer.com 2012
//Answer to: http://stackoverflow.com/questions/1376440/javascript-replacing-the-escape-character-in-a-string-literal/10785991#10785991
//To better demonstrate and understand the string-escaping behavior of JS, take the following example:

//You can see what the string looks like in memory after being parsed by the JS-engine by splitting the string, 
//thus also offering potential (ugly) solutions around this issue:

'file:///C:\funstuff\buildtools\viewer.html'.split('')
//>
 ["f", "i", "l", "e", ":", "/", "/", "/", "C", ":", "", "u", "n", "s", "t", "u",
  "f", "f", "", "u", "i", "l", "d", "t", "o", "o", "l", "s", "", "i", "e", "w",
  "e", "r", ".", "h", "t", "m", "l"]

'file:///C:\funstuff\buildtools\viewer.html'.split('').map( function(e){
     return e.charCodeAt()
});
//>
[102, 105, 108, 101, 58, 47, 47, 47, 67, 58, 12, 117, 110, 115, 116, 117, 102,
 102, 8, 117, 105, 108, 100, 116, 111, 111, 108, 115, 11, 105, 101, 119, 101, 
 114, 46, 104, 116, 109, 108]
//>in Hex values by applying .toString(16)
["66", "69", "6c", "65", "3a", "2f", "2f", "2f", "43", "3a", "c", "75", "6e", 
 "73", "74", "75", "66", "66", "8", "75", "69", "6c", "64", "74", "6f", "6f", 
 "6c", "73", "b", "69", "65", "77", "65", "72", "2e", "68", "74", "6d", "6c"]
//Basically the single backslash escapes the following character, 
//thus giving rise to unexpected results, if the escaping-context is not heeded.

//#Solution:

//Through a look-up-table, you can restore many errantly escaped characters if they
//lie outside the printable ASCII character range of `\x20-\x7F`. 
//For the example above for instance, 12 or \x0c [ 12..toString(16) ] would become '\\'+'v', and so on.

//PS: Be aware that a loss of information occured, and you are trying to restore information 
//through contextual- or meta- information, meaning in your case that the string is in the printable ASCII range.

//Please share any implementations with the community. Cheers!