lssergey

from itertools import product


def combinations(d):
    """
    >>> d = {'a': [2, 5, 6], 'b': [8, 3, 6]}
    >>> combinations(d)
    [{'a': 2, 'b': 8}, {'a': 2, 'b': 3}, {'a': 2, 'b': 6}, {'a': 5, 'b': 8}, {'a': 5, 'b': 3}, {'a': 5, 'b': 6}, {'a': 6, 'b': 8}, {'a': 6, 'b': 3, {'a': 6, 'b': 6}]
    """
    return [dict(combo) for combo in product(*[

lssergey

# Python does not have tail recursion optimization, 
# so this function can't handle too deep data structures.
# This piece of code was written as a practicing task.

def flatten(l):
    nested = None
    for i, e in enumerate(l):
        if isinstance(e, list):
            nested = e; break
    if nested is not None: