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Publish AWS Lambda Layer for Python Package with 1 Command ⚡️
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#!/bin/bash | |
# EXAMPLE USAGE: ./publish-lambda-layer.sh numpy | |
# check if a package name was provided | |
if [ -z "$1" ]; then | |
echo "Please provide the name of the Python package you want to publish to Lambda as the first argument to this script." | |
exit 1 | |
fi | |
# install the AWS CLI if not already installed | |
if ! [ -x "$(command -v aws)" ]; then | |
echo "Installing the AWS CLI..." | |
pip3 install awscli --upgrade | |
fi | |
# create a deployment package | |
echo "Creating deployment package..." | |
package_name="$1" | |
package_zip="$package_name.zip" | |
mkdir $package_name | |
mkdir $package_name/python | |
pip3 install --target ./$package_name/python $package_name | |
cd $package_name | |
zip -r ../$package_name.zip . | |
cd .. | |
# get the package version | |
package_version=$(pip3 freeze | grep "$package_name==") | |
# publish the deployment package as a Lambda layer | |
echo "Publishing deployment package as a Lambda layer..." | |
aws lambda publish-layer-version \ | |
--layer-name "$package_name" \ | |
--zip-file fileb://"$package_zip" \ | |
--description "$package_name v$package_version" \ | |
--compatible-runtimes python3.10 | |
# clean up | |
rm -rf "$package_name" "$package_zip" |
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