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October 31, 2021 19:31
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Reversing part of a linked list
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#include<bits/stdc++.h> | |
struct ListNode{ | |
int data; | |
ListNode *next; | |
}; | |
class LinkedListReversal{ | |
private: | |
//reverse a linked list | |
ListNode* reverse(ListNode *head){ | |
ListNode* prevNode = NULL; | |
ListNode* currNode = head; | |
while(currNode){ | |
ListNode* next = currNode->next; | |
currNode->next = prevNode; | |
prevNode = currNode; | |
currNode = next; | |
} | |
return prevNode; | |
} | |
public: | |
//append to end of linked list | |
void append(ListNode** head, int newData){ | |
ListNode* newNode = new ListNode(); | |
ListNode *last = *head; | |
newNode->data = newData; | |
newNode->next = NULL; | |
if (*head == NULL){ | |
*head = newNode; | |
return; | |
} | |
while (last->next != NULL){ | |
last = last->next; | |
} | |
last->next = newNode; | |
return; | |
} | |
//print linked list elements | |
void printList(ListNode* head){ | |
while (head != NULL) { | |
std::cout << head->data << " "; | |
head = head->next; | |
} | |
std::cout << std::endl; | |
} | |
//reversing part of linked list | |
ListNode* reversePart(ListNode* head, int m, int n){ | |
// single element in selected part | |
if(m == n || m > n) | |
return head; | |
// Initialize pointers | |
ListNode* revStart = NULL; | |
ListNode* revEnd = NULL; | |
ListNode* revPrev = NULL; | |
ListNode* revNext = NULL; | |
ListNode* currNode = head; | |
int i = 1; | |
// place all pointers in their respective positions | |
while(currNode && i <= n){ | |
if( i < m) | |
revPrev = currNode; | |
if(i == m) | |
revStart = currNode; | |
if(i == n){ | |
revEnd = currNode; | |
revNext = currNode->next; | |
} | |
currNode = currNode->next; | |
i++; | |
} | |
revEnd->next = NULL; | |
// reverse selected part | |
revEnd = reverse(revStart); | |
//rejoin the reversed part back to original list by shifting pointers | |
if(revPrev) | |
revPrev->next = revEnd; | |
else | |
head = revEnd; | |
revStart->next = revNext; | |
return head; | |
} | |
ListNode* reversePartII(ListNode* head, int m, int n){ | |
//start cannot be smaller than end position | |
if(m == n || m > n) | |
return head; | |
ListNode* prevNode = NULL; | |
ListNode* currNode = NULL; | |
// skip the first m nodes | |
for(int i = 1; currNode != NULL && i < m; i++){ | |
prevNode = currNode; | |
currNode = currNode->next; | |
} | |
// assign pointers to start and end of selected part | |
ListNode* revStart = currNode; | |
ListNode* revEnd = NULL; | |
// reverse the selected part | |
for(int i = 1; currNode != NULL && i <= n-m+1; i++){ | |
ListNode* next = currNode->next; | |
currNode->next = revEnd; | |
revEnd = currNode; | |
} | |
// reassign pointers and rejoin to main list | |
if(revStart != NULL){ | |
revStart->next = currNode; | |
if(prevNode != NULL) | |
prevNode->next = revEnd; | |
else | |
head = revEnd; | |
} | |
return head; | |
} | |
}; | |
int main(){ | |
LinkedListReversal ll; | |
ListNode* head = NULL; | |
for(int i = 1; i <= 7; i++){ | |
ll.append(&head, i); | |
} | |
std::cout << "Original List" << std::endl; | |
ll.printList(head); | |
std::cout << "Reversed Lists" << std::endl; | |
ListNode* reversedHead = ll.reversePart(head, 3, 5); | |
ll.printList(reversedHead); | |
ListNode* reversedHeadII = ll.reversePartII(head, 3, 5); | |
ll.printList(reversedHeadII); | |
return 0; | |
} |
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