Dictionary attack based password cracker.

Pass Cracker.py

"""
"42","deleted","9bd4d2724d163588e2ab6460ec111c63","deleted","deleted","1","someone@server.com","TZ851BASC9J5543U15T34Z","6eb8977fa505b44099017213d8f3714fd38a7816","0","0","deleted","7c5494c5f4203654","1385366270","1401585007","0","0",NULL

hash_ # 2
salt  # 12

How it works:
There is a file in which there is users data. In this user data all of the
information is present to get a password. i.e pass hash, salt etc look to
the abouve line.
This script take one line at-a-time and using a custom method to get the
actual hash. see the pass_hash function.
Then it use dictionary attack to crack the pass.
"""

import hashlib
import csv
import threading


pass_found = open(r'pass_found.txt', 'w')

def pass_hash(salt, pass_):
    sha = hashlib.sha1(bytes(salt + pass_, 'utf-8')).hexdigest()
    md5 = hashlib.md5(bytes(salt + sha, 'utf-8')).hexdigest()
    return md5

def is_same(current_user=None):
    with open(r'wordlist.txt', newline='') as file:
        count = 0
        prev_count = 0
        print('Thread started: ' + current_user[6])
        for word in file:
            if count == prev_count + 100000:
                print(str(count) + ' checked.')
                prev_count = count
            if pass_hash(current_user[12], word.strip()) == current_user[2]:
                print('Found:' + word)
                pass_found.write(current_user[6] + ',' +
                                 current_user[1] + ',' +
                                 word + '\n')
                pass_found.flush()
                break
            count += 1
        print('No pass found.')
        print('Thread successfully completed')

if __name__ == '__main__':
    with open(r'isc_users.csv', newline='') as file:
        users = list(csv.reader(file))
        for current_user in users:
            t = threading.Thread(target=is_same, args=(current_user,))
            t.start()

Traceback (most recent call last):
File "hashcrack.py", line 34, in
with open(r'isc_users.csv', newline='') as file:
TypeError: 'newline' is an invalid keyword argument for this function