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Gist containing solution to two problems:
a)Write a function (in any language) which takes 'n' as an argument and prints all the numbers from 1 to 'n', except that: (a) if a number is divisible by 3, it should print 'Hip' instead of the number, (b) if divisible by 5 it should print 'Hop', and (c) if divisible by 3 & 5, it should print 'Whazaa' i…
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//snippet for generating random numbers for input.txt :https://gist.github.com/manuj10/5701051 | |
//sol for part b. | |
#include<stdio.h> | |
#include<conio.h> | |
int main() | |
{FILE *filepointer; | |
filepointer=fopen("input.txt","r"); | |
static int i=0,freq[5000],j=0,max=0; | |
while(!feof(filepointer)) | |
{ | |
fscanf(filepointer,"%d",&i); | |
freq[i]++; | |
if(i>=max) | |
max=i; | |
} | |
printf("number-->frequency\n"); | |
for(j=0;j<=max;j++) | |
{printf("%d------->%d\n",j,freq[j]);} | |
getch(); | |
return 0;} |
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//solution for part a | |
#include<stdio.h> | |
#include<conio.h> | |
int main() | |
{int input,i; | |
printf("Enter the number\n"); | |
scanf("%d",&input); | |
for(i=1;i<=input;i++) | |
{if((i%3||i%5)==0) | |
printf("Whazaa\n"); | |
else if(i%3==0) | |
printf("Hip\n"); | |
else if(i%5==0) | |
printf("Hop\n"); | |
else | |
printf("%d\n",i);} | |
getch(); | |
return 0;} |
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