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/* | |
Kth Missing Positive Number | |
Given an array arr of positive integers sorted in a strictly increasing order, and an integer k. | |
Find the kth positive integer that is missing from this array. | |
Example 1: | |
Input: arr = [2,3,4,7,11], k = 5 | |
Output: 9 | |
Explanation: The missing positive integers are [1,5,6,8,9,10,12,13,...]. The 5th missing positive integer is 9. | |
Example 2: | |
Input: arr = [1,2,3,4], k = 2 | |
Output: 6 | |
Explanation: The missing positive integers are [5,6,7,...]. The 2nd missing positive integer is 6. | |
Constraints: | |
1 <= arr.length <= 1000 | |
1 <= arr[i] <= 1000 | |
1 <= k <= 1000 | |
arr[i] < arr[j] for 1 <= i < j <= arr.length | |
*/ | |
const findKthPositive = (arr, k) => { | |
let tracker = 0; | |
for (let i = 0; i < arr.length; i += 1) { | |
const curr = arr[i]; | |
while (curr !== (tracker + 1)) { | |
tracker += 1; | |
k -= 1; | |
if (k === 0) return tracker; | |
} | |
tracker += 1; | |
} | |
return tracker + k; | |
} | |
const arr1 = [2, 3, 4, 7, 11]; | |
console.log(findKthPositive(arr1, 5), "should be 9") | |
const arr2 = [1, 2, 3, 4]; | |
console.log(findKthPositive(arr2, 2), " should be 6"); | |
const arr3 = [1, 2]; | |
console.log(findKthPositive(arr3, 1), " should be 3"); |
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