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Last active May 9, 2018 18:35
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little fun creating a square root function
#!/usr/bin/env python
################################################################################
# The MIT License (MIT)
#
# Copyright (c) 2018 Mark LaPerriere
#
# Permission is hereby granted, free of charge, to any person obtaining a copy
# of this software and associated documentation files (the "Software"), to deal
# in the Software without restriction, including without limitation the rights
# to use, copy, modify, merge, publish, distribute, sublicense, and/or sell
# copies of the Software, and to permit persons to whom the Software is
# furnished to do so, subject to the following conditions:
#
# The above copyright notice and this permission notice shall be included in
# all copies or substantial portions of the Software.
#
# THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR
# IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,
# FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE
# AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER
# LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM,
# OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN
# THE SOFTWARE.
################################################################################
from __future__ import print_function
PRECISION_DIGITS = 10
PRECISION = 1.0 / (10 ** PRECISION_DIGITS)
print("Find the square root to {} decimals".format(PRECISION))
def sqrt_(a):
n = a
if n < 0:
n /= -1
g = int(n)
i = 0
while (g*g > n):
g = g >> 1
i += 1
print("{0} guess (took {1} reductions): {2}".format(a, i, g))
while (not (-PRECISION < (g*g-n) < PRECISION)):
g = (g + (n / g)) / 2
return float(round(g, PRECISION_DIGITS))
print(sqrt_(10)) # 3.1622776602
print(sqrt_(-25)) # 5.0
print(sqrt_(9)) # 3.0
print(sqrt_(100)) # 10.0
print(sqrt_(4)) # 2.0
print(sqrt_(21)) # 4.582575695
print(sqrt_(716044081)) # 26759.0
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