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68–95–99.7 rule

$$\large P_{r}(\mu - 1\sigma \leq \mu + 1\sigma ) \approx 68.27%$$ $$\large P_{r}(\mu - 2\sigma \leq \mu + 3\sigma ) \approx 95.45%$$ $$\large P_{r}(\mu - 3\sigma \leq \mu + 3\sigma ) \approx 99.73%$$

Normal distribution

$$ \large f(x) = \frac {1}{\sigma\sqrt{2\pi}} e^{-0.5\big(\frac{x -\mu} {\sigma}\big)^{2}}$$

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