FizzBuzz without using explicit "if"

fizzbuzz.py

def fizzbuzz(number):
    """
    Return 'Fizz' if `num` is divisible by 3,
    return 'Buzz' if `num` is divisible by 5,
    return 'FizzBuzz' if `num` is divisible both by 3 and 5.

    If `num` isn't divisible neither by 3 nor by 5, return `number`.

    Example:
        fizzbuzz(3) # Fizz
        fizzbuzz(5) # Buzz
        fizzbuzz(15) # FizzBuzz
        fizzbuzz(8) # 8
    """
    fizz = ((number % 3 == 0) and "Fizz") or ''  # It's divisible by 3, then it is "Fizz" or otherwise empty string
    buzz = ((number % 5 == 0) and "Buzz") or ''  # It's divisible by 5, then it is "Buzz" or otherwise empty string
    return fizz + buzz or number