simple python client/server socket binary stream

client.py

import socket

HOST = 'localhost'
PORT = 9876
ADDR = (HOST,PORT)
BUFSIZE = 4096
videofile = "videos/royalty-free_footage_wien_18_640x360.mp4"

bytes = open(videofile).read()

print len(bytes)

client = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
client.connect(ADDR)

client.send(bytes)

client.close()

server.py

import socket

HOST = ''
PORT = 9876
ADDR = (HOST,PORT)
BUFSIZE = 4096

serv = socket.socket(socket.AF_INET, socket.SOCK_STREAM)

serv.bind(ADDR)
serv.listen(5)

print 'listening ...'

while True:
  conn, addr = serv.accept()
  print 'client connected ... ', addr
  myfile = open('testfile.mov', 'w')

  while True:
    data = conn.recv(BUFSIZE)
    if not data: break
    myfile.write(data)
    print 'writing file ....'

  myfile.close()
  print 'finished writing file'
  conn.close()
  print 'client disconnected'

Cosmic! And simple to understand

I tried the code given, but unfortunately I am getting the error mentioned below:
Traceback (most recent call last):
File "client.py", line 13, in
bytes = open(videoFile,encoding="utf8").read()
File "C:\Users\hP\AppData\Local\Programs\Python\Python36-32\lib\codecs.py", line 321, in decode
(result, consumed) = self._buffer_decode(data, self.errors, final)
UnicodeDecodeError: 'utf-8' codec can't decode byte 0xb3 in position 5: invalid start byte

please how can i receive the file when i sent it via this code?

The problem is because the open function is not used to save or send in binary form.
Client:
Change the line 9 to: bytes = open(videofile, 'rb').read()
Server:
Change the line 18 to: myfile = open('testfile.mov', 'wb')

Instead of video file can I use this code on webcam?

simple handy code and easy to understand for beginners! thanks!