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Hanoi Tower Program in Java to calculate token time to solve it and its order
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//Algorithm and implemention by Masoud Bonabi | |
import java.util.Stack; | |
public class Main { | |
static Stack[] pipes; | |
final static int N = 3; | |
public static void solve(final int srcPipe,final int destPipe,final int solveFor){ | |
if(solveFor == 0) | |
return ; | |
int finalPurpose = ((Integer)pipes[srcPipe].get(pipes[srcPipe].size()-solveFor)).intValue(); | |
int unusedPipe = findUnusedPipe(srcPipe,destPipe); | |
if( solveFor > 1 ) | |
solve(srcPipe, unusedPipe, solveFor-1); | |
int i = pipes[destPipe].size(); | |
if(i>0){ | |
i--; | |
while(i>=0 && ((Integer)pipes[destPipe].get(i)).intValue()<finalPurpose) | |
i--; | |
i = pipes[destPipe].size() - i - 1; | |
if( i > 0 ) | |
solve(destPipe, unusedPipe, i); | |
} | |
pipes[destPipe].push(pipes[srcPipe].pop()); | |
solve(unusedPipe,destPipe,solveFor-1); | |
} | |
private static int findUnusedPipe(int a,int b) { | |
boolean [] total = new boolean[3]; | |
total[a] = true; | |
total[b] = true; | |
int answer = 0; | |
for(int i=0;i<total.length;i++) | |
if(!total[i]){ | |
answer = i; | |
break; | |
} | |
return answer; | |
} | |
public static void main(String[] args) { | |
long a = System.currentTimeMillis(); | |
initPipes(N); | |
solve(0,2,N); | |
print(); | |
System.out.println((System.currentTimeMillis() - a)/1000.0f + "seconds"); | |
} | |
private static void print() { | |
for(int i=0;i<3;i++){ | |
System.out.print(i+1+": "); | |
for(int j=0;j<pipes[i].size();j++) | |
System.out.print(((Integer)pipes[i].get(j)).intValue()+" "); | |
System.out.println(); | |
} | |
} | |
private static void initPipes(int numberOfDisks) { | |
pipes = new Stack[3]; | |
for(int i=0;i<pipes.length;i++) | |
pipes[i] = new Stack(); | |
for(int i=numberOfDisks;i>0;i--) | |
pipes[0].push(new Integer(i)); | |
} | |
} |
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