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December 24, 2020 15:12
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solution
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/* | |
we either win, or we learn. | |
*/ | |
#include <bits/stdc++.h> | |
#define HS ios_base::sync_with_stdio(false);cin.tie(NULL); | |
#define ll long long | |
#define pll pair<ll,ll> | |
#define pb push_back | |
#define M 100'000'0007 | |
#define lc '\n' | |
using namespace std; | |
int main() | |
{ | |
HS | |
string s; | |
cin>>s; | |
ll n=s.length(); | |
ll dp[n],dp1[n]; | |
ll l=0,r=-1; | |
for(ll i=0;i<n;i++) | |
{ | |
ll k; | |
if(i>r) | |
{ | |
k=1; | |
} | |
else | |
{ | |
k=min(r-i+1,dp[l+r-i]); | |
} | |
while(i-k>=0 and i+k<n and s[i-k]==s[i+k]) | |
{ | |
k++; | |
} | |
dp[i]=k--; | |
if(i+k>r) | |
{ | |
l=i-k; | |
r=i-k; | |
} | |
} | |
l=0,r=-1; | |
for(ll i=0;i<n;i++) | |
{ | |
ll k; | |
if(i>r) | |
{ | |
k=0; | |
} | |
else | |
{ | |
k=min(r-i,dp1[l+r-i]); | |
} | |
while(i-k-1>=0 and i+k<n and s[i-k-1]==s[i+k]) | |
{ | |
k++; | |
} | |
dp1[i]=k--; | |
if(i+k>r) | |
{ | |
l=i-k; | |
r=i-k; | |
} | |
} | |
ll mask=0; | |
for(auto i:dp) | |
{ | |
mask+=i; | |
} | |
for(auto i:dp1) | |
{ | |
mask+=i; | |
} | |
cout<<mask<<lc; | |
return 0; | |
} |
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