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Population Stability Index and Information Value function
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def pop_diff(popA, popB, bin_boundaries=None, num_bins=10): | |
""" | |
Compute difference between two populations using the PSI / IV formula | |
$$\Sigma_{i} (p_i^B - p_i^a)*\ln(\frac{p_i^B}{p_i^A})$$ | |
Note: | |
Counts missing values in a separate bin to test for information and shift. | |
Raises ValueError if popA has no nans but popB does. | |
Arguments: | |
popA (pandas.Series): Base population, e.g. goods or train | |
popB (pandas.Series): Compared population, e.g. bads or test | |
bin_boundaries (list or None): Boundaries between bins, excluding bottom and top which are +-np.inf by default | |
num_bins (int): Number of buckets to use if bin_boundaries is not used | |
Returns: | |
(float) diff, (pandas.DataFrame) summary | |
Examples: | |
>>> psi = pop_diff(df_train['age'], df_test['age'], bin_boundaries=[17, 21, 40, 65]) | |
>>> iv_age = pop_diff(df_good['age'], df_bad['age'], num_buckets=20) | |
""" | |
# create binning | |
if bin_boundaries is None: | |
bin_boundaries = [ | |
popA.quantile((i+1)*(1.0/num_bins)) | |
for i in range(0, num_bins-1) | |
] | |
bin_boundaries = [-np.inf] + bin_boundaries + [np.inf] | |
# make a table of bin counts (histogram) | |
pop_diff = pd.DataFrame.from_dict({ | |
'start': bin_boundaries[:-1], | |
'end': bin_boundaries[1:], | |
}) | |
pop_diff['countA'] = pop_diff.apply( | |
lambda row: ((row['start'] < popA) & (popA <= row['end'])).sum(), | |
axis=1) | |
pop_diff['countB'] = pop_diff.apply( | |
lambda row: ((row['start'] < popB) & (popB <= row['end'])).sum(), | |
axis=1) | |
# analyze missing values - if they exist we create a separate bin | |
popA_missing = len(popA) - popA.count() | |
popB_missing = len(popB) - popB.count() | |
if popA_missing: | |
# create a bin for missing | |
pop_diff = pop_diff.append({ | |
'start': np.nan, | |
'end': np.nan, | |
'countA': popA_missing, | |
'countB': popB_missing | |
}, ignore_index=True) | |
elif popB_missing: | |
raise ValueError('Population B has missing although population A doesnt. This might indicate a quality problem.') | |
# apply psi / iv formula | |
pop_diff['ratioA'] = pop_diff['countA']/len(popA) | |
pop_diff['ratioB'] = pop_diff['countB']/len(popB) | |
pop_diff['diff'] = (pop_diff['ratioB'] - pop_diff['ratioA'])*np.log(pop_diff['ratioB']/pop_diff['ratioA']) | |
# compute the totals and format the result | |
s = pop_diff.sum() | |
s.name = 'total' | |
return s['diff'], pop_diff.append(s) |
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