flatten_dict.py

# useful way to flatten dictionary representing i.e. path to file and content
# now fixed in case of running it again

def flatten_dict(d,path=(),paths=None, sep='/'):
    if paths==None: paths=[]
    if isinstance(d,dict):
        for k,v in d.items():
            flatten_dict(v,path+(k,),paths)
        return paths
    else:
        paths.append( { sep+sep.join(path) : d } )