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The rucksack problem solution in Pascal
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program rucksack; | |
uses math; | |
type THistory = array [0..10000,0..10000] of integer; | |
tItem= record | |
val,size:integer; | |
end; | |
TItems = array [1..10000] of tItem; | |
var fin,fout: text; | |
maxSize,maxItems,curSize,counter,counter2:integer; | |
History:THIstory; | |
items: TItems; | |
begin | |
assign(fin,'in.txt'); | |
reset(fin); | |
readln(fin, maxSize,maxItems); | |
for counter:=1 to maxITEMS do | |
readln(fin,items[counter].val,items[counter].size); | |
history[maxSize,maxItems]:=-1; | |
for counter:=1 to max(maxSize,maxItems) do begin | |
history[counter,0]:=0; | |
history[0,counter]:=0; | |
end; | |
counter:=1; | |
while (history[maxsize,maxItems]=-1) do begin | |
for counter2:=0 to items[counter].size-1 do | |
history[counter2,counter]:=history[counter2,counter-1]; | |
curSize:=items[counter].size; | |
for counter2:=items[counter].size to maxSize do begin | |
history[counter2,counter]:= | |
max(curSize+history[maxSize-curSize,counter-1], | |
history[counter2,counter-1]); | |
writeln(history[counter2,counter]); | |
readln; | |
end; | |
writeln('############'); | |
readln; | |
inc(counter); | |
end; | |
writeln(history[maxsize,maxItems]); | |
readln; | |
end. |
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