Created
March 29, 2022 00:32
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Makes a power set provided a set using
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# Maximo Xavier deLeon 03/28/2022 | |
# Makes a power set provided a set | |
def removeDuplciates(l): | |
nl=list() | |
for i in l: | |
if i not in nl: | |
nl.append(i) | |
return nl | |
def main(): | |
# define origional set and remove duplicates if they exist | |
originalSet = removeDuplciates(['a','b','c','c']) | |
# define integer k and power set | |
k = len(originalSet) | |
powerSet = list() | |
# iterate 2**k times by definition the cardinality of a power set | |
for i in range(2**k): | |
# create binary index for list comprehension | |
subset_index = [int(i) for i in str('{0:b}'.format(i,"b"))] | |
subset_index = [0]*(k-len(subset_index)) + subset_index | |
# list comprehension to generate list of elements determined by binary number index | |
subset = [originalSet[j-k] if subset_index[j-k] == 1 else None for j in range(k)] | |
# remove the None values and append power set | |
subset = list(filter(None, subset)) | |
powerSet.append(subset) | |
#print out stuff | |
print('A: {}\nP(A): {}\n{}'.format(originalSet,powerSet,'='*10)) | |
print('|A|: {}\n|P(A)|: {}'.format(k,2**k)) | |
if __name__ == '__main__': | |
main() |
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