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August 29, 2015 14:04
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options choices list - generate all the possible combinations of a given number of choices and options to choose from
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def binarylist(choices) | |
list = Array.new(2**choices) | |
(2**choices).times do |x| | |
list[x]=[] | |
choices.times do |y| | |
if (x & 2**y)!=0 | |
list[x] << 1 | |
else | |
list[x] << 0 | |
end | |
end | |
end | |
return list | |
end | |
def optionschoiceslist(options,choices) | |
list = binarylist(choices) | |
current = 1 | |
3.upto(options) do | |
newlist = [ ] | |
list.length.times do |i| | |
row = list[i] | |
if row.include?(current) | |
index = [ ] | |
row.length.times do |j| | |
if row[j]==current | |
index << j | |
end | |
end | |
templist = binarylist(index.length) | |
templist = templist.collect{|e1| e1.collect {|e2| e2 + current }} | |
templist.length.times do |j| | |
temprow = row.dup | |
index.length.times do |k| | |
temprow[index[k]] = templist[j][k] | |
end | |
newlist << temprow | |
end | |
else | |
newlist << row | |
end | |
end | |
current = current + 1 | |
list = newlist | |
end | |
return list | |
end | |
optionschoiceslist(4,3) | |
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