A basic example of using mbostock's weekday.js gist to to plot only weekdays using a linear scale. The resulting charts will not show gaps where weekends would be.
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Weekdays
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date | value | |
---|---|---|
01/5/2014 | 1 | |
02/5/2014 | 2 | |
05/5/2014 | 1 | |
06/5/2014 | 2 | |
08/5/2014 | 2 |
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<!DOCTYPE html> | |
<html> | |
<head> | |
<meta charset="utf-8"> | |
<script src="http://d3js.org/d3.v3.min.js"></script> | |
<script src="weekday.js"></script> | |
<title>Scale test</title> | |
<style> | |
body { | |
font-family: 'helvetica neue'; | |
font-size: .8em; | |
} | |
.line { | |
fill: none; | |
stroke: black; | |
stroke-width: 1px; | |
} | |
.axis line, | |
.axis path { | |
stroke-width: 1px; | |
stroke: black; | |
fill: none; | |
} | |
.dots circle { | |
fill: #555; | |
fill-opacity: .5; | |
} | |
</style> | |
</head> | |
<body> | |
<div id="chart"></div> | |
<script> | |
var margin = {top: 20, right: 50, bottom: 50, left: 20}, | |
width = 960 - margin.left - margin.right, | |
height = 502 - margin.top - margin.bottom; | |
var parseDate = d3.time.format("%d/%m/%Y").parse; | |
var dayCount = 0; | |
var x = d3.scale.linear() | |
.range([0, width - margin.right]); | |
var y = d3.scale.linear() | |
.range([0, height - margin.left]); | |
var dateFormat = d3.time.format('%a %b %d'); | |
var xAxis = d3.svg.axis() | |
.scale(x) | |
.orient("below") | |
.tickFormat(function (d) { return dateFormat(weekday.invert(d)); }); | |
var yAxis = d3.svg.axis() | |
.scale(y) | |
.orient("right"); | |
var line = d3.svg.line() | |
.x(function(d) { return x(d.weekday); }) | |
.y(function(d) { return y(d.value); }); | |
var svg = d3.select("#chart").append("svg") | |
.attr("width", width + margin.left + margin.right) | |
.attr("height", height + margin.top + margin.bottom); | |
d3.csv("data.csv", type, function(error, data) { | |
x.domain(d3.extent(data, function(d) { return d.weekday; })); | |
y.domain(d3.extent(data, function(d) { return parseFloat(d.value); })) | |
svg.append("path") | |
.datum(data) | |
.attr("class", "line") | |
.attr("transform", "translate(" + margin.left + "," + margin.top + ")") | |
.attr("d", line); | |
svg.append("g") | |
.attr("class", "x axis") | |
.attr("transform", "translate(" + margin.left + "," + (margin.top + height + 20) + ")") | |
.call(xAxis) | |
.selectAll("text") | |
.attr("dy", ".35em"); | |
svg.append("g") | |
.attr("class", "y axis") | |
.attr("transform", "translate(" + (width + 20) + "," + margin.top + ")") | |
.call(yAxis) | |
.selectAll("text") | |
.attr("dy", ".35em"); | |
svg.append("g") | |
.attr("class", "dots") | |
.attr("transform", "translate(" + margin.left + "," + margin.top + ")") | |
.selectAll("circle") | |
.data(data) | |
.enter() | |
.append("circle") | |
.attr("r", 5) | |
.attr("cx", function(d) { return x(d.weekday); }) | |
.attr("cy", function(d) { return y(d.value); });; | |
}); | |
function type(d) { | |
d.date = parseDate(d.date); | |
d.weekday = weekday(d.date); | |
return d | |
} | |
</script> | |
</body> | |
</html> |
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// This function originated from mbostock's gist: https://gist.github.com/mbostock/5827353 | |
weekday = (function() { | |
// Returns the weekday number for the given date relative to January 1, 1970. | |
function weekday(date) { | |
var weekdays = weekdayOfYear(date), | |
year = date.getFullYear(); | |
while (--year >= 1970) weekdays += weekdaysInYear(year); | |
return weekdays; | |
} | |
// Returns the date for the specified weekday number relative to January 1, 1970. | |
weekday.invert = function(weekdays) { | |
var year = 1970, | |
yearWeekdays; | |
// Compute the year. | |
while ((yearWeekdays = weekdaysInYear(year)) <= weekdays) { | |
++year; | |
weekdays -= yearWeekdays; | |
} | |
// Compute the date from the remaining weekdays. | |
var days = weekdays % 5, | |
day0 = ((new Date(year, 0, 1)).getDay() + 6) % 7; | |
if (day0 + days > 4) days += 2; | |
return new Date(year, 0, (weekdays / 5 | 0) * 7 + days + 1); | |
}; | |
// Returns the number of weekdays in the specified year. | |
function weekdaysInYear(year) { | |
return weekdayOfYear(new Date(year, 11, 31)) + 1; | |
} | |
// Returns the weekday number for the given date relative to the start of the year. | |
function weekdayOfYear(date) { | |
var days = d3.time.dayOfYear(date), | |
weeks = days / 7 | 0, | |
day0 = (d3.time.year(date).getDay() + 6) % 7, | |
day1 = day0 + days - weeks * 7; | |
return Math.max(0, days - weeks * 2 | |
- (day0 <= 5 && day1 >= 5 || day0 <= 12 && day1 >= 12) // extra saturday | |
- (day0 <= 6 && day1 >= 6 || day0 <= 13 && day1 >= 13)); // extra sunday | |
} | |
return weekday; | |
})(); |
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