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Task: Sequence C contains elements from A if they are present in B p times, and p is prime number
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import kotlin.math.* | |
//Task: Sequence C contains elements from A if they are present in B p times, and p is prime number | |
fun main() { | |
val a = arrayListOf(2, 3, 9, 2, 5, 1, 3, 7, 10) | |
val b = intArrayOf(2, 1, 3, 4, 3, 10, 6, 6, 1, 7, 10, 10, 10) | |
val c = ArrayList<Int>(a) | |
//check every unique number in B sequence | |
for(i in b.distinct()){ | |
if(isPrimeNumber(countNumber(i, b))) | |
//if we didn't care about original contents of A, at this point we could remove the values from A and we would get the expected C. | |
// while loop to remove all of the instances of checked number. | |
while(c.contains(i)) | |
c.remove(i) | |
} | |
//And just to prove that it works, we print it all out | |
for(i in c) | |
println(i) | |
} | |
//Naive primality test | |
//This works well for small set of data, with the complexity of O(n). | |
fun isPrimeNumber(n : Int) : Boolean { | |
if (n < 2) | |
return false | |
val upperRange = floor(sqrt(n.toDouble())).toInt() | |
for(i in 2..upperRange) { | |
val division = n%i | |
if(division == 0) | |
return false | |
} | |
return true | |
} | |
fun countNumber(n : Int, sequence : IntArray) : Int{ | |
val predicate : (Int) -> Boolean = { it == n} | |
return sequence.count(predicate) | |
} |
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