A demonstration of how to chose a random point uniformly within an annulus. Compare to naïve sampling.
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February 9, 2016 01:53
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Annulus Sampling II
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license: gpl-3.0 |
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<!DOCTYPE html> | |
<meta charset="utf-8"> | |
<canvas width="960" height="500"></canvas> | |
<script src="//d3js.org/d3.v3.min.js"></script> | |
<script> | |
var canvas = d3.select("canvas"), | |
canvasNode = canvas.node(), | |
context = canvasNode.getContext("2d"); | |
var numSamplesPerFrame = 50, | |
numSamples = 0; | |
var width = canvasNode.width, | |
height = canvasNode.height, | |
outerRadius = (Math.min(width, height) - 5) / 2, | |
innerRadius = outerRadius / 4; | |
var outerRadius2 = outerRadius * outerRadius, | |
innerRadius2 = innerRadius * innerRadius, | |
k = outerRadius2 - innerRadius2; | |
context.translate(width / 2, height / 2); | |
context.save(); | |
context.beginPath(); | |
context.arc(0, 0, outerRadius, 0, 2 * Math.PI); | |
context.moveTo(innerRadius, 0); | |
context.arc(0, 0, innerRadius, 2 * Math.PI, 0); | |
context.fillStyle = "rgba(0,0,0,.2)"; | |
context.fill("evenodd"); | |
context.restore(); | |
context.fillStyle = "rgba(0,0,0,.5)"; | |
d3.timer(function() { | |
for (var i = 0; i < numSamplesPerFrame; ++i) { | |
var a = Math.random() * 2 * Math.PI, | |
r = Math.sqrt(Math.random() * k + innerRadius2), | |
x = r * Math.cos(a), | |
y = r * Math.sin(a); | |
context.beginPath(); | |
context.arc(x, y, 1, 0, 2 * Math.PI); | |
context.fill(); | |
} | |
return ++numSamples > 1000; | |
}); | |
</script> |
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