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@mburke05
Created November 6, 2015 20:33
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import unittest
NUMB = str(7316717653133062491922511967442657474235534919493496983520312774506326239578318016984801869478851843858615607891129494954595017379583319528532088055111254069874715852386305071569329096329522744304355766896648950445244523161731856403098711121722383113622298934233803081353362766142828064444866452387493035890729629049156044077239071381051585930796086670172427121883998797908792274921901699720888093776657273330010533678812202354218097512545405947522435258490771167055601360483958644670632441572215539753697817977846174064955149290862569321978468622482839722413756570560574902614079729686524145351004748216637048440319989000889524345065854122758866688116427171479924442928230863465674813919123162824586178664583591245665294765456828489128831426076900422421902267105562632111110937054421750694165896040807198403850962455444362981230987879927244284909188845801561660979191338754992005240636899125607176060588611646710940507754100225698315520005593572972571636269561882670428252483600823257530420752963450)
def prod_of_big_number(number, n):
"""Takes a string and returns the max possible product of consecutive digits (digits) in
that string."""
min_index = 0
max_index = min_index + n
high_num = 0
while max_index <= len(number):
#check for zeros to save some computation
zero_flag = number[min_index:max_index].rfind('0')
if zero_flag >= 0:
min_index = min_index + zero_flag + 1
max_index = min_index+n
continue
#obtaining the reduced product
curr_num = 1
for x in number[min_index:max_index]:
curr_num *= int(x)
#store high result
if curr_num > high_num:
high_num = curr_num
min_index += 1
max_index += 1
return high_num
class AdjacentProductTestCase(unittest.TestCase):
def test_4_digits(self):
self.assertEqual(prod_of_big_number(NUMB, 4), 5832)
def test_5_digits(self):
self.assertEqual(prod_of_big_number(NUMB, 5), 40824)
def test_13_digits(self):
self.assertEqual(prod_of_big_number(NUMB, 13), 23514624000)
unittest.main()
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