md2perpe

venv/
*.pyc

md2perpe

from itertools import count, cycle

for (n, d3, d5) in zip(count(0), cycle([True, False, False]), cycle([True, False, False, False, False])):
  print(("Fizz" if d3 else "")+("Buzz" if d5 else "") or str(n))

md2perpe

# Solve:
#    LETA
#   +TALL
#   =====
#   CACHE

for a in range(10):
  for e in range(10):
    for l in range(10):
      for t in range(10):

md2perpe

*.o

md2perpe

# https://www.facebook.com/groups/270834543757117/?creative_provider_id=admin_can_post_branded_content&notif_id=1607539332809717&notif_t=qp_notifs_pups_notification_to_mall_dogfood_1730789509&ref=notif

N = 10

for i in range(N):
  print("He" * i)
  print("Ha" * i)
  print("Hi" * i)

md2perpe

# Maximum unattacked squares

def attacked_from_square(r, c):
    attacked = set([])
    for i in range(5):
        attacked.add((r,i))
        attacked.add((i,c))
        if 0<=r+i<5 and 0<=c+i<5:
            attacked.add((r+i,c+i))
        if 0<=r+i<5 and 0<=c-i<5:

md2perpe

################
known_domains = {
  "hotmail.com": [],
  "gmail.com": [],
  "yahoo.com": [],
  "mail.ru": [],
}
notfound = []
################

md2perpe

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md2perpe

#include <stdio.h>

#define R 50
#define C 150
#define K 50

int main()
{
    int r, c;
    for (r=0; r<R; r++)

md2perpe

import datetime

FIRST_MONDAY = datetime.datetime(1970, 1, 5, tzinfo=datetime.timezone.utc).timestamp()

HOUR = 3600
DAY  = 24*HOUR
WEEK = 7*DAY

CLOSE_HOUR = 22
OPEN_HOUR  =  8