Access path of file in module (even if in zip file) in Python

load_file_from_module.py

# Source: https://stackoverflow.com/a/20885799/991496

# IMPORANT: There needs to be a `__init__.py` in `your.lib.resources` 
# otherwise `pkg_resources.path` throws a FileNotFoundError saying "<resource> resource not found in <package_name>".
import your.lib.resources
try:
    import importlib.resources as pkg_resources
except ImportError:
    # Try backported to PY<37 `importlib_resources`.
    import importlib_resources as pkg_resources
with pkg_resources.path(your.lib.resources, "load_fcs.R") as path:
    with open(path, "rb") as f:
        # do something