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| def countPairsWithDiffK(arr, n, k): | |
| count = 0 | |
| for i in range(0,n): | |
| for j in range(i,n): | |
| if (arr[i] - arr[j] == k or arr[j] - arr[i] == k ): | |
| count = count+1 | |
| return count |
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