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June 9, 2017 05:32
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Difference of two large numbers
http://www.geeksforgeeks.org/difference-of-two-large-numbers/
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// C++ program to find difference of two large numbers. | |
#include<bits/stdc++.h> | |
using namespace std; | |
// Returns true if str1 is smaller than str2. | |
bool isSmaller(string str1, string str2) | |
{ | |
// Calculate lengths of both string | |
int n1 = str1.length(), n2 = str2.length(); | |
if (n1 < n2) | |
return true; | |
if (n2 < n1) | |
return false; | |
for (int i=0; i<n1; i++) | |
if (str1[i] < str2[i]) | |
return true; | |
else if (str1[i] > str2[i]) | |
return false; | |
return false; | |
} | |
// Function for find difference of larger numbers | |
string findDiff(string str1, string str2) | |
{ | |
// Before proceeding further, make sure str1 | |
// is not smaller | |
if (isSmaller(str1, str2)) | |
swap(str1, str2); | |
// Take an empty string for storing result | |
string str = ""; | |
// Calculate length of both string | |
int n1 = str1.length(), n2 = str2.length(); | |
// Reverse both of strings | |
reverse(str1.begin(), str1.end()); | |
reverse(str2.begin(), str2.end()); | |
int carry = 0; | |
// Run loop till small string length | |
// and subtract digit of str1 to str2 | |
for (int i=0; i<n2; i++) | |
{ | |
// Do school mathematics, compute difference of | |
// current digits | |
int sub = ((str1[i]-'0')-(str2[i]-'0')-carry); | |
// If subtraction is less then zero | |
// we add then we add 10 into sub and | |
// take carry as 1 for calculating next step | |
if (sub < 0) | |
{ | |
sub = sub + 10; | |
carry = 1; | |
} | |
else | |
carry = 0; | |
str.push_back(sub + '0'); | |
} | |
// subtract remaining digits of larger number | |
for (int i=n2; i<n1; i++) | |
{ | |
int sub = ((str1[i]-'0') - carry); | |
carry = 0; | |
str.push_back(sub + '0'); | |
} | |
// reverse resultant string | |
reverse(str.begin(), str.end()); | |
return str; | |
} | |
// Driver code | |
int main() | |
{ | |
string str1 = "12"; | |
string str2 = "198111"; | |
cout << findDiff(str1, str2); | |
return 0; | |
} |
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// C++ program to find difference of two large numbers. | |
#include<bits/stdc++.h> | |
using namespace std; | |
// Returns true if str1 is smaller than str2, | |
// else false. | |
bool isSmaller(string str1, string str2) | |
{ | |
// Calculate lengths of both string | |
int n1 = str1.length(), n2 = str2.length(); | |
if (n1 < n2) | |
return true; | |
if (n2 > n1) | |
return false; | |
for (int i=0; i<n1; i++) | |
{ | |
if (str1[i] < str2[i]) | |
return true; | |
else if (str1[i] > str2[i]) | |
return false; | |
} | |
return false; | |
} | |
// Function for finding difference of larger numbers | |
string findDiff(string str1, string str2) | |
{ | |
// Before proceeding further, make sure str1 | |
// is not smaller | |
if (isSmaller(str1, str2)) | |
swap(str1, str2); | |
// Take an empty string for storing result | |
string str = ""; | |
// Calculate lengths of both string | |
int n1 = str1.length(), n2 = str2.length(); | |
int diff = n1 - n2; | |
// Initially take carry zero | |
int carry = 0; | |
// Traverse from end of both strings | |
for (int i=n2-1; i>=0; i--) | |
{ | |
// Do school mathematics, compute difference of | |
// current digits and carry | |
int sub = ((str1[i+diff]-'0') - | |
(str2[i]-'0') - | |
carry); | |
if (sub < 0) | |
{ | |
sub = sub+10; | |
carry = 1; | |
} | |
else | |
carry = 0; | |
str.push_back(sub + '0'); | |
} | |
// subtract remaining digits of str1[] | |
for (int i=n1-n2-1; i>=0; i--) | |
{ | |
if (str1[i]=='0' && carry) | |
{ | |
str.push_back('9'); | |
continue; | |
} | |
int sub = ((str1[i]-'0') - carry); | |
if (i>0 || sub>0) // remove preceding 0's | |
str.push_back(sub+'0'); | |
carry = 0; | |
} | |
// reverse resultant string | |
reverse(str.begin(), str.end()); | |
return str; | |
} | |
// Driver code | |
int main() | |
{ | |
string str1 = "88"; | |
string str2 = "1079"; | |
cout << findDiff(str1, str2); | |
return 0; | |
} |
Not using any built in methods. And the list represents the precision integers
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Would you be able to find difference of two lists
In python.
Example listA= [1,5,9]
ListB=[1,2,9]
Answer= [3,0]