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How to type safe merge objects which identical types in TypeScript
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type IfEquals<T1, T2, IfEqual = T2, Else = never> = (< | |
Interim | |
>() => Interim extends T1 ? true : false) extends < | |
Interim | |
>() => Interim extends T2 ? true : false | |
? IfEqual | |
: Else; | |
type Entries<T> = { | |
[K in keyof T]: [K, T[K]]; | |
}[keyof T][]; | |
// Unfortunately `Object.entries` isn't well typed :/ | |
// to avoid errors in its usage - here is small type-safe wrapper | |
function entries<T>(obj: T): Entries<T> { | |
return Object.entries(obj) as any; | |
} | |
function mergeObjects<T1, T2 extends T1, TResultField>( | |
first: T1, | |
second: IfEquals<T1, T2>, | |
merge: (first: T1, second: IfEquals<T1, T2>, key: keyof T1) => TResultField | |
): { [Key in keyof T1]: TResultField } { | |
return entries(first).reduce( | |
(acc, [key]) => ({ | |
...acc, | |
[key]: merge(first, second, key), | |
}), | |
{} as { [Key in keyof T1]: TResultField } | |
); | |
} | |
// === example usage ==== | |
const LABELS: Labels = { | |
a: 'label a', | |
b: 'label b', | |
}; | |
const VALUES: Values = { | |
a: 'value a', | |
b: 'value b', | |
}; | |
type Labels = { | |
a: string; | |
b: string; | |
}; | |
type Values = { | |
a: string; | |
b: string; | |
}; | |
const result = mergeObjects(LABELS, VALUES, (label, value, key) => ({ | |
label: label[key], | |
value: value[key], | |
})); | |
console.log('result:', result); | |
// result: { | |
// a: { label: 'label a', value: 'value a' }, | |
// b: { label: 'label b', value: 'value b' } | |
// } |
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