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@michalfita
Last active December 28, 2021 19:47
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Ruby solution to conversion of text into a phone number
def n2t(text)
letters = ["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"," "]
numbers = [ 2 , 2, 2 , 3 , 3 , 3 , 4 , 4 , 4 , 5 , 5 , 5 , 6 , 6 , 6 , 7 , 7 , 7 , 7 , 8 , 8 , 8 , 9 , 9 , 9 , 9 , 0 ]
output = String.new()
for ti in 0..text.length
for li in 0..letters.length
if letters[li] == text[ti] then
output << numbers[li].to_s
end
end
end
print output
end
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