-
-
Save michax/af3855270cf051d3bbbb to your computer and use it in GitHub Desktop.
a very fast algorithm for getting the circumcircle from a triangle - http://www.exaflop.org/docs/cgafaq/cga1.html#Subject 1.04
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
function circumcircle(a, b, c) { | |
this.a = a | |
this.b = b | |
this.c = c | |
var A = b.x - a.x, | |
B = b.y - a.y, | |
C = c.x - a.x, | |
D = c.y - a.y, | |
E = A * (a.x + b.x) + B * (a.y + b.y), | |
F = C * (a.x + c.x) + D * (a.y + c.y), | |
G = 2 * (A * (c.y - b.y) - B * (c.x - b.x)), | |
minx, miny, dx, dy | |
/* If the points of the triangle are collinear, then just find the | |
* extremes and use the midpoint as the center of the circumcircle. */ | |
if(Math.abs(G) < 0.000001) { | |
minx = Math.min(a.x, b.x, c.x) | |
miny = Math.min(a.y, b.y, c.y) | |
dx = (Math.max(a.x, b.x, c.x) - minx) * 0.5 | |
dy = (Math.max(a.y, b.y, c.y) - miny) * 0.5 | |
this.x = minx + dx | |
this.y = miny + dy | |
this.r = dx * dx + dy * dy | |
} | |
else { | |
this.x = (D*E - B*F) / G | |
this.y = (A*F - C*E) / G | |
dx = this.x - a.x | |
dy = this.y - a.y | |
this.r = dx * dx + dy * dy | |
} | |
} |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment