[Jenkins] Groovy script to delete all jenkins jobs that match a regex pattern

deleteJenkinsJobs.groovy

import jenkins.model.*

i = 1

def matchedJobs = Jenkins.instance.items.findAll { job ->
    job.name =~ /my_regex_here/
}
    
matchedJobs.each { job ->
    println i++ + " >> This job will be deleted: " + job.name
    //job.delete()
}

deleteJenkinsJobsWithFolders.groovy

import jenkins.*
import jenkins.model.*
import hudson.*
import hudson.model.*

import hudson.scm.*
import hudson.tasks.*
import com.cloudbees.hudson.plugins.folder.*

i = 1
jen = Jenkins.instance

jen.getItems().each{
    if(it instanceof Folder){
        processFolder(it)
    }else{
        processJob(it)
    }
}

void processJob(Item job){
  if (job.name ==~ /.*None$/){
    println i++ + " >> This job will be deleted: " + job.name
    //job.delete()
  }
}

void processFolder(Item folder){
    folder.getItems().each{
        if(it instanceof Folder){
            processFolder(it)
        }else{
            processJob(it)
        }
    }
}