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Last active May 15, 2019 21:48
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Levenshtein Distance
/**
* @license MIT
* Copyright 2019 @andrei-m
*
* See original which this code is based on:
* https://gist.github.com/andrei-m/982927/0efdf215b00e5d34c90fdc354639f87ddc3bd0a5
*
* Basic modifications include using ES6 `const` and `let`. Additionally
* condenses if statement. Changes are somewhat trivial overall :)
*
* Permission is hereby granted, free of charge, to any person obtaining a
* copy of this software and associated documentation files (the "Software"),
* to deal in the Software without restriction, including without limitation
* the rights to use, copy, modify, merge, publish, distribute, sublicense,
* and/or sell copies of the Software, and to permit persons to whom the
* Software is furnished to do so, subject to the following conditions:
* The above copyright notice and this permission notice shall be included
* in all copies or substantial portions of the Software.
* THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS
* OR IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF
* MERCHANTABILITY, FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT.
* IN NO EVENT SHALL THE AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY
* CLAIM, DAMAGES OR OTHER LIABILITY, WHETHER IN AN ACTION OF CONTRACT,
* TORT OR OTHERWISE, ARISING FROM, OUT OF OR IN CONNECTION WITH THE
* SOFTWARE OR THE USE OR OTHER DEALINGS IN THE SOFTWARE.
*
* @description
* Computes a Levenshtein Distance.
*
* This computes a Levenshtein Distance which most simply is a
* distance in out-of-place letters, wrong letters, and missing
* letters.
*
* @see https://en.wikipedia.org/wiki/Levenshtein_distance
* @param {String} a The first word.
* @param {String} b The second word.
*
* @returns {Number} The Levenshtein Distance between `a` and `b`.
*/
const getLevenshteinDistance = (a, b) => {
if (a.length == 0 || b.length == 0) {
return 0;
}
const matrix = [];
// Increment along the first column of each row.
let i;
for(i = 0; i <= b.length; i++){
matrix[i] = [i];
}
// Increment each column in the first row.
let j;
for (j = 0; j <= a.length; j++) {
matrix[0][j] = j;
}
// Fill in the rest of the matrix
for (i = 1; i <= b.length; i++) {
for (j = 1; j <= a.length; j++) {
if (b.charAt(i-1) == a.charAt(j-1)) {
matrix[i][j] = matrix[i-1][j-1];
} else {
matrix[i][j] = Math.min(matrix[i-1][j-1] + 1, // substitution
Math.min(matrix[i][j-1] + 1, // insertion
matrix[i-1][j] + 1)); // deletion
}
}
}
return matrix[b.length][a.length];
}
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