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@mikeyang01
Created February 22, 2019 14:50
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public class LinkedList_reverse {
public static void main(String[] args) {
Node head = new Node(0);
Node node1 = new Node(1);
Node node2 = new Node(2);
Node node3 = new Node(3);
head.setNext(node1);
node1.setNext(node2);
node2.setNext(node3);
// 打印反转前的链表
Node h = head;
while (null != h) {
System.out.print(h.getData() + " ");
h = h.getNext();
}
// 调用反转方法
head = Reverse1(head);
System.out.println("\n**************************");
// 打印反转后的结果
while (null != head) {
System.out.print(head.getData() + " ");
head = head.getNext();
}
}
/**
* 递归,在反转当前节点之前先反转后续节点
*/
public static Node Reverse1(Node head) {
// head看作是前一结点,head.getNext()是当前结点,reHead是反转后新链表的头结点
if (head == null || head.getNext() == null) {
return head;// 若为空链或者当前结点在尾结点,则直接还回
}
Node reHead = Reverse1(head.getNext());// 先反转后续节点head.getNext()
head.getNext().setNext(head);// 将当前结点的指针域指向前一结点
head.setNext(null);// 前一结点的指针域令为null;
return reHead;// 反转后新链表的头结点
}
}
class Node {
private int Data;// 数据域
private Node Next;// 指针域
public Node(int Data) {
// super();
this.Data = Data;
}
public int getData() {
return Data;
}
public void setData(int Data) {
this.Data = Data;
}
public Node getNext() {
return Next;
}
public void setNext(Node Next) {
this.Next = Next;
}
}
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