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@mikeyang01
Created February 22, 2019 12:31
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import java.util.Stack;
import java.util.Queue;
import java.util.LinkedList;
public class TreeMap {
class BST<E extends Comparable<E>> {
private class Node {
public E e;
public Node left, right;
public Node(E e) {
this.e = e;
left = null;
right = null;
}
}
private Node root;
private int size;
public BST() {
root = null;
size = 0;
}
public int size() {
return size;
}
public boolean isEmpty() {
return size == 0;
}
// 向二分搜索树中添加新的元素e
public void add(E e) {
root = add(root, e);
}
// 向以node为根的二分搜索树中插入元素e,递归算法
// 返回插入新节点后二分搜索树的根
private Node add(Node node, E e) {
if (node == null) {
size++;
return new Node(e);
}
if (e.compareTo(node.e) < 0)
node.left = add(node.left, e);
else if (e.compareTo(node.e) > 0)
node.right = add(node.right, e);
return node;
}
// 看二分搜索树中是否包含元素e
public boolean contains(E e) {
return contains(root, e);
}
// 看以node为根的二分搜索树中是否包含元素e, 递归算法
private boolean contains(Node node, E e) {
if (node == null)
return false;
if (e.compareTo(node.e) == 0)
return true;
else if (e.compareTo(node.e) < 0)
return contains(node.left, e);
else // e.compareTo(node.e) > 0
return contains(node.right, e);
}
// 前序遍历以node为根的二分搜索树, 递归算法
private void preOrder(Node node) {
if (node == null)
return;
System.out.print(node.e + " ");
preOrder(node.left);
preOrder(node.right);
}
// 二分搜索树的非递归前序遍历
public void preOrderNR() {
if (root == null)
return;
Stack<Node> stack = new Stack<>();
stack.push(root);
while (!stack.isEmpty()) {
Node cur = stack.pop();
System.out.print(cur.e + " ");
if (cur.right != null)
stack.push(cur.right);
if (cur.left != null)
stack.push(cur.left);
}
}
// 中序遍历以node为根的二分搜索树, 递归算法
private void inOrder(Node node) {
if (node == null)
return;
inOrder(node.left);
System.out.print(node.e + " ");
inOrder(node.right);
}
// 后序遍历以node为根的二分搜索树, 递归算法
private void postOrder(Node node) {
if (node == null)
return;
postOrder(node.left);
postOrder(node.right);
System.out.print(node.e + " ");
}
// 二分搜索树的层序遍历
public void levelOrder() {
if (root == null)
return;
Queue<Node> q = new LinkedList<>();
q.add(root);
while (!q.isEmpty()) {
Node cur = q.remove();
System.out.print(cur.e + " ");
if (cur.left != null)
q.add(cur.left);
if (cur.right != null)
q.add(cur.right);
}
}
@Override
public String toString() {
StringBuilder res = new StringBuilder();
generateString(root, 0, res);
return res.toString();
}
// 生成以node为根节点,深度为depth的描述二叉树的字符串
private void generateString(Node node, int depth, StringBuilder res) {
if (node == null) {
res.append(generateDepthString(depth) + "null\n");
return;
}
res.append(generateDepthString(depth) + node.e + "\n");
generateString(node.left, depth + 1, res);
generateString(node.right, depth + 1, res);
}
private String generateDepthString(int depth) {
StringBuilder res = new StringBuilder();
for (int i = 0; i < depth; i++)
res.append("--");
return res.toString();
}
}
public static void main(String[] args) {
TreeMap main = new TreeMap();
BST<Integer> bst = main.new BST<>();
int[] nums = { 5, 3, 6, 8, 4, 2 };
for (int num : nums)
bst.add(num);
/////////////////
// 5 //
// / \ //
// 3 6 //
// / \ \ //
// 2 4 8 //
/////////////////
bst.preOrder(bst.root);
System.out.println("pre");
bst.inOrder(bst.root);
System.out.println("mid");
bst.postOrder(bst.root);
System.out.println("post");
bst.levelOrder();
System.out.println("level");
}
}
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