sum array with NaN with two approaches. Create a new array or pass through a do loop in Julia

add_up_with_NaN.jl

foo = [ones(1000), NaN]

function removeNaN_sum(x::Array)      
  newa = typeof(x[1])[]
    for i in 1:length(x)
      if x[i] <= max(x)
       push!(newa, x[i])
       end
    end
  sum(newa)
end

function doremoveNaN_sum(x::Array)
  sum(x) do x  
    isnan(x) ? 0 : x  
  end
end
julia> removeNaN_sum(foo)
1000.0

julia> doremoveNaN_sum(foo)
1000.0

julia> timetrial(removeNaN_sum, foo, 100)
0.01151830281

julia> timetrial(doremoveNaN_sum, foo, 100)
0.00011032616