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@mindplace
Created April 4, 2016 03:23
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def to_binary(number)
returning = []
if number.odd?
returning << 1
number -= 1
end
while number > 0
i = 1
while 2 ** i <= number
if 2 ** (i + 1) > number
returning[i] = 1
number -= (2 ** i)
break
end
i += 1
end
end
returning.map{|num| num.nil? ? "0" : "#{num}"}.reverse.join.to_i
end
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