Created
April 17, 2014 00:50
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A solution for cs50's "caesar" problem: using a simple Caesar cipher
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/** | |
* caesar.c | |
* | |
* Peter Downs | |
* | |
* A code for encrypting text with a simple Caesar cipher. | |
*/ | |
#include <cs50.h> | |
#include <stdio.h> | |
#include <stdlib.h> | |
#include <string.h> | |
#include <ctype.h> | |
// Get the key to the cipher | |
int main(int argc, string argv[]) | |
{ | |
string key = argv[1]; | |
if (argc != 2) | |
{ | |
printf("Please give me a valid key"); | |
return 1; | |
} | |
else | |
{ | |
// Convert the string to an integer | |
int k = atoi(key) % 26; | |
// Check that it is a valid key | |
if (k == 0) | |
{ | |
printf("Invalid key. Try again\n"); | |
return 1; | |
} | |
// Get the text to encrypt | |
string plntxt = GetString(); | |
if (plntxt != NULL) | |
{ | |
// Encrypt and print | |
for (int i = 0, n = strlen(plntxt); i < n; i++) | |
{ | |
int c = 0; | |
// Check if text is upper case or lower case | |
// If so, switch to alphabet number and encrypt | |
if (isupper(plntxt[i])) | |
{ | |
c = (((int)plntxt[i] - 65 + k) % 26) + 65; | |
printf("%c", (char) c); | |
} | |
else if (islower(plntxt[i])) | |
{ | |
c = (((int)plntxt[i] - 97 + k) % 26) + 97; | |
printf("%c", (char) c); | |
} | |
else | |
{ | |
printf("%c", plntxt[i]); | |
} | |
} | |
printf("\n"); | |
return 0; | |
} | |
} | |
} | |
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