Created
May 18, 2015 19:53
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Solution to Daily Programmer 2015-05-18
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#https://www.reddit.com/r/dailyprogrammer/comments/36cyxf/20150518_challenge_215_easy_sad_cycles | |
def next_digit(n, b): | |
return sum([int(d)**b for d in str(n)]) | |
def recover_cycle(nodes, end): | |
tmp = [] | |
while nodes: | |
node = nodes.pop() | |
tmp.append(node) | |
if node == end: | |
break | |
return tmp[::-1] | |
def find_sad_cycle(val, base, max_depth = 1000): | |
nodes = set([val]) | |
path = [val] | |
i = 0 | |
while i < max_depth: | |
i += 1 | |
val = next_digit(val, base) | |
if val in nodes: | |
#then we have a cycle | |
print 'Cycle Found', recover_cycle(path, val) | |
break | |
else: | |
nodes.add(val) | |
path.append(val) | |
def floyds_cycle_finding(val, base): | |
#implementation of Floyds cycle detecion algorithm adapted to sad-cycle problem | |
f = lambda x : next_digit(x, base) | |
tortoise = f(val) | |
hare = f(f(val)) | |
while tortoise != hare: | |
tortoise = f(tortoise) | |
hare = f(f(hare)) | |
#find the starting point of cycle mue | |
mu = 0 | |
tortoise = val | |
while tortoise != hare: | |
tortoise = f(tortoise) | |
hare = f(hare) | |
mu += 1 | |
#find the length of the shortest cycle | |
lam = 1 | |
hare = f(tortoise) | |
while tortoise != hare: | |
hare = f(hare) | |
lam += 1 | |
print mu,lam | |
tmp = val | |
for _ in range(mu): | |
tmp = f(tmp) | |
path = [tmp] | |
for _ in range(lam): | |
tmp = f(tmp) | |
path.append(tmp) | |
print path | |
if __name__ == "__main__": | |
find_sad_cycle(12, 2) | |
find_sad_cycle(117649, 5) | |
find_sad_cycle(2, 6) | |
find_sad_cycle(7, 7) | |
find_sad_cycle(14, 3) | |
floyds_cycle_finding(12, 2) | |
floyds_cycle_finding(117649, 5) | |
floyds_cycle_finding(2, 6) | |
floyds_cycle_finding(7, 7) |
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