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Triangle sum of odd numbers
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// 1/10/2016 (Great Question*) | |
Given the triangle of consecutive odd numbers: | |
1 | |
3 5 | |
7 9 11 | |
13 15 17 19 | |
21 23 25 27 29 | |
... | |
Calculate the row sums of this triangle from the row index (starting at index 1) e.g.: | |
rowSumOddNumbers(1); // 1 | |
rowSumOddNumbers(2); // 3 + 5 = 8 | |
// 1 | |
// 3 5, 2*1 + 1 row 2 * 1 | |
// 7 9 11, 2*3 + 1 row 3 * 3 | |
// 13 15 17 19, 2*6 + 1 row 4 * 6 | |
// 21 23 25 27 29, 2*10 + 1 row 5 * 10 | |
// 31 33 35 37 39 41, 2*15 + 1 | |
// 1 1-1 | |
// 2 2-3 | |
// 3 4-6 | |
// 4 7-10 | |
// 5 11-15 | |
// 6 16-21 | |
// 6) 15 = 1+2+3+4+5 | |
// 5) 10 = 1+2+3+4 | |
// 4) 6 = 1+2+3 | |
// 3) 3=1+2 | |
// 2) 1=1 | |
// 1) 0 | |
My Solution: | |
function addRow(n) { | |
var total=0; | |
for (var i=0;i<n;i++){ | |
total+=i | |
// console.log(total) | |
} | |
var firstNum=2*total+1 | |
// console.log(firstNum) | |
var sum=0; | |
for (j=0;j<n;j++){ | |
sum+=firstNum | |
firstNum+=2 | |
console.log('in loop ', sum) | |
} | |
return sum | |
} | |
addRow(42) |
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return n*n*n