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def find_frequent_subsequences(seq, K, minsup, maxgap): | |
S = seq | |
L = [] | |
# Map each individual symbol to its position in the sequence | |
for k in range(0, len(seq)): | |
L.append((seq[k],k)) | |
# Reduce [(symbol1, position1), (symbol1, position2), ... ] to {symbol1: [position1, position2, ...]} | |
Lr = {} | |
for k in range(0, len(L)): | |
if L[k][0] in Lr: | |
Lr[L[k][0]].append(L[k][1]) | |
else: | |
Lr[L[k][0]] = [L[k][1]] | |
# Filter out the symbols with less than minsup support | |
Lk = dict((k,v) for k,v in Lr.items() if len(v) >= minsup) | |
Lr = Lk | |
# Recursively combine->reduce | |
for k in range(1, K): | |
L = [] | |
for l1 in Lk: | |
for l2 in Lr: | |
# Combine symbol1,..,symbolN-1 and symbolN | |
subseq = tuple(l1)+tuple(l2) | |
for v1 in Lk[l1]: | |
for v2 in Lr[l2]: | |
if k == 1: | |
v = [v1, v2] | |
else: | |
v = v1 + [v2] | |
# Keep only those that are sorted in order with a maximum gap of maxgap | |
if all([v[i] < v[i+1] and v[i+1]-v[i] < maxgap+1 for i in range(0, len(v)-1)]): | |
L.append((subseq, v)) | |
# Reduce again and filter | |
Lk = {} | |
for k in range(0, len(L)): | |
if L[k][0] in Lk: | |
Lk[L[k][0]].append(L[k][1]) | |
else: | |
Lk[L[k][0]] = [L[k][1]] | |
Lk = dict((k,v) for k,v in Lk.items() if len(v) >= minsup) | |
# Return a record with gap symbols and frequent subsequences | |
record = {} | |
for lk in Lk: | |
length = len(lk) | |
gap_symbols = [] | |
for i in range(0, len(Lk[lk])): | |
gap = S[Lk[lk][i][0]+1:Lk[lk][i][1]] | |
if gap: | |
gap_symbols += gap | |
record[lk] = (len(Lk[lk]), gap_symbols) | |
return record | |
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